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受欢迎的代数 >

2z^2-z-1=0

解答

2 z^{2} - z - 1 = 0

解答

z = 1, z = - \frac{1}{2}

+1

十进制

z = 1, z = - 0.5

求解步骤

2 z^{2} - z - 1 = 0

使用求根公式求解

z_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 1 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 1) = 3

z_{1, 2} = \frac{- ( - 1 ) \pm 3}{2 \cdot 2}

将解分隔开

z_{1} = \frac{- ( - 1 ) + 3}{2 \cdot 2}, z_{2} = \frac{- ( - 1 ) - 3}{2 \cdot 2}

z = \frac{- ( - 1 ) + 3}{2 \cdot 2} : 1

z = \frac{- ( - 1 ) - 3}{2 \cdot 2} : - \frac{1}{2}

二次方程组的解是:

z = 1, z = - \frac{1}{2}

作图

流行的例子

-x(x+3)=2(x^2+1)

- x (x + 3) = 2 (x^{2} + 1)

solvefor q,-0.3q^2+36q=-3q-100

so l v e f or q, - 0.3 q^{2} + 36 q = - 3 q - 100

1/8 x^2+2x+16=0

\frac{1}{8} x^{2} + 2 x + 16 = 0

2 (x + 1)^{2} = 18

solvefor x,3x^2-6y^2+3xy+x+2y=0

so l v e f or x, 3 x^{2} - 6 y^{2} + 3 x y + x + 2 y = 0