2m^2+8m+8=0

解答

2 m^{2} + 8 m + 8 = 0

m = - 2

求解步骤

2 m^{2} + 8 m + 8 = 0

使用求根公式求解

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 8 = 0

m_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 2}

m = \frac{- 8}{2 \cdot 2}

\frac{- 8}{2 \cdot 2} = - 2

m = - 2

二次方程组的解是:

m = - 2

321.0069 x^{2} - 5130.1778 x + 14682.6031 = 0

x (5 x - 2) = 24

- x^{2} - 12 x + 9 = 0

t^{2} - 8 t + 10 = 0

so l v e f or x, f = (5 m - 10) 2 x^{2} + 3 x + 4