6x-3x^2-3=0

解答

6 x - 3 x^{2} - 3 = 0

x = 1

求解步骤

6 x - 3 x^{2} - 3 = 0

改写成标准形式

a x^{2} + b x + c = 0

- 3 x^{2} + 6 x - 3 = 0

使用求根公式求解

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 3 ) ( - 3 )}{2 ( - 3 )}

6^{2} - 4 (- 3) (- 3) = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 ( - 3 )}

x = \frac{- 6}{2 ( - 3 )}

\frac{- 6}{2 ( - 3 )} = 1

x = 1

二次方程组的解是:

x = 1

\frac{3}{5} x^{2} - 1 = 2

co m pl e t es q u a re x^{2} - 19 x

q u a d r a t i c f or m u l a 3 x^{2} - x - 2 = 0

- x^{2} + 16 x - 63 = 0

co m pl e t es q u a re m^{2} - 12 m + 26 = 0