What are the solutions to the equation quadraticformula (x^2-6)/2-(x^2+4)/4 =5 ?

The solutions to the equation quadraticformula (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6

Find the zeros of quadraticformula (x^2-6)/2-(x^2+4)/4 =5

The zeros of quadraticformula (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6

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\frac{x ^{2} - 6}{2} - \frac{x ^{2} + 4}{4} = 5

x = 6, x = - 6

Solution steps

\frac{x ^{2} - 6}{2} - \frac{x ^{2} + 4}{4} = 5

Find Least Common Multiplier of

2, 4 : 4

Multiply by LCM=

4

\frac{x ^{2} - 6}{2} \cdot 4 - \frac{x ^{2} + 4}{4} \cdot 4 = 5 \cdot 4

Simplify

2 (x^{2} - 6) - (x^{2} + 4) = 20

Expand

2 (x^{2} - 6) - (x^{2} + 4) : x^{2} - 16

x^{2} - 16 = 20

Move

20

to the left side

x^{2} - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 36 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 36) = 12

x_{1, 2} = \frac{- 0 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 12}{2 \cdot 1}, x_{2} = \frac{- 0 - 12}{2 \cdot 1}

x = \frac{- 0 + 12}{2 \cdot 1} : 6

x = \frac{- 0 - 12}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 6, x = - 6

2 x^{2} - 18 x = - 28

5 x^{2} = 40 x

x = 0.55 \cdot (6.71 - x \cdot 0.75)^{2}

x, 4 x^{2} = 0

x^{2} + 10 x - 3 = 0

What are the solutions to the equation quadraticformula (x^2-6)/2-(x^2+4)/4 =5 ?
The solutions to the equation quadraticformula (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6
Find the zeros of quadraticformula (x^2-6)/2-(x^2+4)/4 =5
The zeros of quadraticformula (x^2-6)/2-(x^2+4)/4 =5 are x=6,x=-6