p^2+13p+36=0

解

p^{2} + 13 p + 36 = 0

p = - 4, p = - 9

解答ステップ

p^{2} + 13 p + 36 = 0

解くとthe二次式

p_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 1 \cdot 36}{2 \cdot 1}

1 3^{2} - 4 \cdot 1 \cdot 36 = 5

p_{1, 2} = \frac{- 13 \pm 5}{2 \cdot 1}

解を分離する

p_{1} = \frac{- 13 + 5}{2 \cdot 1}, p_{2} = \frac{- 13 - 5}{2 \cdot 1}

p = \frac{- 13 + 5}{2 \cdot 1} : - 4

p = \frac{- 13 - 5}{2 \cdot 1} : - 9

二次equationの解:

p = - 4, p = - 9