7/3 x+6/3 x= 6/2 x+3/2 x+8

解

\frac{7}{3} x + \frac{6}{3} x = \frac{6}{2} x + \frac{3}{2} x + 8

x = - 48

解答ステップ

\frac{7}{3} x + \frac{6}{3} x = \frac{6}{2} x + \frac{3}{2} x + 8

\frac{6}{3} x = 2 x

\frac{7}{3} x + 2 x = \frac{6}{2} x + \frac{3}{2} x + 8

\frac{6}{2} x = 3 x

\frac{7}{3} x + 2 x = 3 x + \frac{3}{2} x + 8

両辺から

3 x + \frac{3}{2} x

を引く

\frac{7}{3} x + 2 x - (3 x + \frac{3}{2} x) = 3 x + \frac{3}{2} x + 8 - (3 x + \frac{3}{2} x)

簡素化

- \frac{1}{6} x = 8

以下で両辺を乗じる:

- 6

x = - 48