x^2+15x+44=0

解

x^{2} + 15 x + 44 = 0

x = - 4, x = - 11

解答ステップ

x^{2} + 15 x + 44 = 0

解くとthe二次式

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 44}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 44 = 7

x_{1, 2} = \frac{- 15 \pm 7}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 15 + 7}{2 \cdot 1}, x_{2} = \frac{- 15 - 7}{2 \cdot 1}

x = \frac{- 15 + 7}{2 \cdot 1} : - 4

x = \frac{- 15 - 7}{2 \cdot 1} : - 11

二次equationの解:

x = - 4, x = - 11