faktorisieren 25x^4-y^6

Lösung

faktorisieren

25 x^{4} - y^{6}

(5 x^{2} + y^{3}) (5 x^{2} - y^{3})

Schritte zur Lösung

25 x^{4} - y^{6}

25 x^{4} = (5 x^{2})^{2}

y^{6} = (y^{3})^{2}

= (5 x^{2})^{2} - (y^{3})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(5 x^{2})^{2} - (y^{3})^{2} = (5 x^{2} + y^{3}) (5 x^{2} - y^{3})

= (5 x^{2} + y^{3}) (5 x^{2} - y^{3})

f a c t or 2 cos^{2} (x) - cos (x)

s im pl i f y \frac{( n + 1 ) ! ( n + 2 )}{( n - 1 ) !}

s im pl i f y p^{\frac{2}{5}} \cdot p^{- 2}

f a c t or 22 x^{3} y^{5} z^{2} - 121 x^{4} y^{3} z

s im pl i f y 8 - (8 x - 15)^{3} - (3 x - 7)^{3}