What is factor 9m^4+14m^2*n^2+25n^4 ?

The solution to factor 9m^4+14m^2*n^2+25n^4 is (3m^2+5n^2+4mn)(3m^2+5n^2-4mn)

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factor 9m^4+14m^2*n^2+25n^4

factor

9 m^{4} + 14 m^{2} \cdot n^{2} + 25 n^{4}

(3 m^{2} + 5 n^{2} + 4 mn) (3 m^{2} + 5 n^{2} - 4 mn)

Solution steps

9 m^{4} + 14 m^{2} n^{2} + 25 n^{4}

Add and subtract

16 m^{2} n^{2}

= 9 m^{4} + 30 m^{2} n^{2} + 25 n^{4} - 16 m^{2} n^{2}

Factor

9 m^{4} + 30 m^{2} n^{2} + 25 n^{4} : (3 m^{2} + 5 n^{2})^{2}

= (3 m^{2} + 5 n^{2})^{2} - 16 m^{2} n^{2}

Apply exponent rules

= (3 m^{2} + 5 n^{2})^{2} - (4 mn)^{2}

Factor

(3 m^{2} + 5 n^{2})^{2} - (4 mn)^{2} : (3 m^{2} + 5 n^{2} + 4 mn) (3 m^{2} + 5 n^{2} - 4 mn)

= (3 m^{2} + 5 n^{2} + 4 mn) (3 m^{2} + 5 n^{2} - 4 mn)

(4 x + 2) (3 x + 2)

- sin^{2} (x) - cos^{2} (x) + sin (x)

\frac{2}{( x - \frac{1}{x} )} - \frac{( \frac{1}{x} )}{( 1 - \frac{1}{x} )}

[\frac{( 27 x ^{7} \cdot y ^{3} )}{( 3 x ^{3} \cdot y )}]^{\frac{1}{2}}

\frac{( 2 ^{n + 1} + 2 ^{n} )}{( 2 ^{n + 4} - 2 ^{n + 1} )}

What is factor 9m^4+14m^2*n^2+25n^4 ?
The solution to factor 9m^4+14m^2*n^2+25n^4 is (3m^2+5n^2+4mn)(3m^2+5n^2-4mn)