化简 ((2x+3*2-6x+9/4 x^2-99-x^2+12x-3))/(12x)

解答

化简

\frac{( 2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x ^{2} - 99 - x ^{2} + 12 x - 3 )}{12 x}

\frac{32 x + 5 x ^{2} - 384}{48 x}

求解步骤

\frac{2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x ^{2} - 99 - x ^{2} + 12 x - 3}{12 x}

化简

2 x + 3 \cdot 2 - 6 x + \frac{9}{4} x^{2} - 99 - x^{2} + 12 x - 3 : \frac{32 x + 5 x ^{2} - 384}{4}

= \frac{\frac{32 x + 5 x ^{2} - 384}{4}}{12 x}

使用分式法则:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{32 x + 5 x ^{2} - 384}{4 \cdot 12 x}

数字相乘:

4 \cdot 12 = 48

= \frac{32 x + 5 x ^{2} - 384}{48 x}

f a c t or p^{2} q^{2} - 64 a^{4}

s im pl i f y (a^{5})^{6}

f a c t or 16 + 4 k^{2}

f a c t or 2 m^{3} + 26 m^{2} + 64 m + 40

s im pl i f y 1 + \frac{( 2 b )}{3} + \frac{( b ^{2} )}{9}