faktorisieren 16a^4*b^6-c^6

Lösung

faktorisieren

16 a^{4} \cdot b^{6} - c^{6}

(4 a^{2} b^{3} + c^{3}) (4 a^{2} b^{3} - c^{3})

Schritte zur Lösung

16 a^{4} b^{6} - c^{6}

16 a^{4} b^{6} = (4 a^{2} b^{3})^{2}

c^{6} = (c^{3})^{2}

= (4 a^{2} b^{3})^{2} - (c^{3})^{2}

Wende Formel zur Differenz von zwei Quadraten an:

x^{2} - y^{2} = (x + y) (x - y)

(4 a^{2} b^{3})^{2} - (c^{3})^{2} = (4 a^{2} b^{3} + c^{3}) (4 a^{2} b^{3} - c^{3})

= (4 a^{2} b^{3} + c^{3}) (4 a^{2} b^{3} - c^{3})

s im pl i f y 2 \frac{x}{x ^{2}} - 9 + \frac{5}{x ^{2}} + x - 6

s im pl i f y 2 (x - 1) (x + 1) - (2 x - 1) (x + 1)

e x p an d (2 - t)^{4}

s im pl i f y x^{2} + \frac{1}{( x ^{2} )} + 2 - 2 x - \frac{2}{x}

e x p an d (a + b)^{3} - 16 (a + b)