zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

4x^3+9x^2+22x+5=0

解答

4 x^{3} + 9 x^{2} + 22 x + 5 = 0

解答

x = - \frac{1}{4}, x = - 1 + 2 i, x = - 1 - 2 i

求解步骤

4 x^{3} + 9 x^{2} + 22 x + 5 = 0

因式分解

4 x^{3} + 9 x^{2} + 22 x + 5 : (4 x + 1) (x^{2} + 2 x + 5)

(4 x + 1) (x^{2} + 2 x + 5) = 0

使用零因数法则： If

ab = 0

then

a = 0

or

b = 0

4 x + 1 = 0 or x^{2} + 2 x + 5 = 0

解

4 x + 1 = 0 : x = - \frac{1}{4}

解

x^{2} + 2 x + 5 = 0 : x = - 1 + 2 i, x = - 1 - 2 i

解为

x = - \frac{1}{4}, x = - 1 + 2 i, x = - 1 - 2 i

作图

流行的例子

x-4=4x^3-3x^2+2x-4

x - 4 = 4 x^{3} - 3 x^{2} + 2 x - 4

-x^3+3x^2+x+3=0

- x^{3} + 3 x^{2} + x + 3 = 0

([(13+x)(13-x)(3+x)(3-x)])/(16)=144

\frac{[ ( 13 + x ) ( 13 - x ) ( 3 + x ) ( 3 - x ) ]}{16} = 144

x^5-3x^2+x+10=0

x^{5} - 3 x^{2} + x + 10 = 0

(x^2+x-6)^2-(x^2+2x+1)^2=0

(x^{2} + x - 6)^{2} - (x^{2} + 2 x + 1)^{2} = 0