What are the solutions to the equation (x+1)^5= 1/32 ?

The solutions to the equation (x+1)^5= 1/32 are x=-1/2

Find the zeros of (x+1)^5= 1/32

The zeros of (x+1)^5= 1/32 are x=-1/2

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(x + 1)^{5} = \frac{1}{32}

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

(x + 1)^{5} = \frac{1}{32}

For

(g (x))^{n} = f (a)

, n is odd, the solution is

Solve

The solution is

x = - \frac{1}{2}

(x + 2)^{2} \cdot (x + 6)^{3} + (x + 2) \cdot (x + 6)^{4} = 0

x^{6} = 5

(3 x - 2) (x^{1}) - (2 x^{3}) (2 - x) = 182 x

(x^{2} - 3 x)^{2} - 16 (x^{2} - 3 x) - 36 = 0

x^{3} - x = 1

What are the solutions to the equation (x+1)^5= 1/32 ?
The solutions to the equation (x+1)^5= 1/32 are x=-1/2
Find the zeros of (x+1)^5= 1/32
The zeros of (x+1)^5= 1/32 are x=-1/2