ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

x^2+3x-(a^2+a-2)=0

解

x^{2} + 3 x - (a^{2} + a - 2) = 0

解

x = a - 1, x = - a - 2

解答ステップ

x^{2} + 3 x - (a^{2} + a - 2) = 0

拡張

x^{2} + 3 x - (a^{2} + a - 2) : x^{2} + 3 x - a^{2} - a + 2

x^{2} + 3 x - a^{2} - a + 2 = 0

解くとthe二次式

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 1 \cdot ( - a ^{2} - a + 2 )}{2 \cdot 1}

簡素化

3^{2} - 4 \cdot 1 \cdot (- a^{2} - a + 2) : 2 a + 1

x_{1, 2} = \frac{- 3 \pm ( 2 a + 1 )}{2 \cdot 1}

解を分離する

x_{1} = \frac{- 3 + 2 a + 1}{2 \cdot 1}, x_{2} = \frac{- 3 - ( 2 a + 1 )}{2 \cdot 1}

x = \frac{- 3 + 2 a + 1}{2 \cdot 1} : a - 1

x = \frac{- 3 - ( 2 a + 1 )}{2 \cdot 1} : - a - 2

二次equationの解:

x = a - 1, x = - a - 2

グラフ

人気の例

(2a+3)x^2-3(a+1)x+4=0

(2 a + 3) x^{2} - 3 (a + 1) x + 4 = 0

3x^2-2x+1=2x^2-3x+7

3 x^{2} - 2 x + 1 = 2 x^{2} - 3 x + 7

x^{2} + 3^{2} = x + 2^{2}

x^{1} + x^{2} = 5

solvefor x,x^2-4y^2-z=0

so l v e f or x, x^{2} - 4 y^{2} - z = 0