(3)x=(x^2=9-3=5)

Lösung

(3) x = (x^{2} = 9 - 3 = 5)

x = \frac{- ( - 3 ) + ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}, x = \frac{- ( - 3 ) - ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}

Schritte zur Lösung

(3) x = (x^{2} = 9 - 3 = 5)

Fasse zusammen

3 x = (x^{2} = 9 - 3 = 5)

Tausche die Seiten

(x^{2} = 9 - 3 = 5) = 3 x

Verschiebe

3 x

auf die linke Seite

x^{2} = 9 - 3 = 5 - 3 x = 0

Schreibe in der Standard Form

a x^{2} + b x + c = 0

= 9 x^{2} - 3 x - 3 = 5 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}

x = \frac{- ( - 3 ) + ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}

x = \frac{- ( - 3 ) - ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{- ( - 3 ) + ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}, x = \frac{- ( - 3 ) - ( - 3 ) ^{2} - 4 = 9 ( - 3 = 5 )}{2 = 9}

(2 x - 3)^{2} - (x + 5)^{2} = 0

0.5 x^{2} - 3 x = - x + 2.5

e = x^{2} - 3 x + 5

(10 - x) (\frac{x}{4 - 3}) = 2

\frac{x}{2} = \frac{( x ^{2} )}{7}