(2m-3)x^2-2x+1=0

解

(2 m - 3) x^{2} - 2 x + 1 = 0

x = \frac{2 + - 8 m + 16}{2 ( 2 m - 3 )}, x = \frac{2 - - 8 m + 16}{2 ( 2 m - 3 )}; m \neq = \frac{3}{2}

解答ステップ

(2 m - 3) x^{2} - 2 x + 1 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( 2 m - 3 ) \cdot 1}{2 ( 2 m - 3 )}

簡素化

(- 2)^{2} - 4 (2 m - 3) \cdot 1 : - 8 m + 16

x_{1, 2} = \frac{- ( - 2 ) \pm - 8 m + 16}{2 ( 2 m - 3 )}; m \neq = \frac{3}{2}

解を分離する

x_{1} = \frac{- ( - 2 ) + - 8 m + 16}{2 ( 2 m - 3 )}, x_{2} = \frac{- ( - 2 ) - - 8 m + 16}{2 ( 2 m - 3 )}

x = \frac{- ( - 2 ) + - 8 m + 16}{2 ( 2 m - 3 )} : \frac{2 + - 8 m + 16}{2 ( 2 m - 3 )}

x = \frac{- ( - 2 ) - - 8 m + 16}{2 ( 2 m - 3 )} : \frac{2 - - 8 m + 16}{2 ( 2 m - 3 )}

二次equationの解:

x = \frac{2 + - 8 m + 16}{2 ( 2 m - 3 )}, x = \frac{2 - - 8 m + 16}{2 ( 2 m - 3 )}; m \neq = \frac{3}{2}