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受欢迎的代数 >

2x^2-5x+(3-k)=0

解答

2 x^{2} - 5 x + (3 - k) = 0

解答

x = \frac{5 + 8 k + 1}{4}, x = \frac{5 - 8 k + 1}{4}

求解步骤

2 x^{2} - 5 x + (3 - k) = 0

整理后得

2 x^{2} - 5 x + 3 - k = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( 3 - k )}{2 \cdot 2}

化简

(- 5)^{2} - 4 \cdot 2 (3 - k) : 8 k + 1

x_{1, 2} = \frac{- ( - 5 ) \pm 8 k + 1}{2 \cdot 2}

将解分隔开

x_{1} = \frac{- ( - 5 ) + 8 k + 1}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 8 k + 1}{2 \cdot 2}

x = \frac{- ( - 5 ) + 8 k + 1}{2 \cdot 2} : \frac{5 + 8 k + 1}{4}

x = \frac{- ( - 5 ) - 8 k + 1}{2 \cdot 2} : \frac{5 - 8 k + 1}{4}

二次方程组的解是:

x = \frac{5 + 8 k + 1}{4}, x = \frac{5 - 8 k + 1}{4}

作图

流行的例子

solvefor x,4x^2+6xy+4y^2=1

so l v e f or x, 4 x^{2} + 6 x y + 4 y^{2} = 1

x^2-x(sqrt(6)-1)-sqrt(6)=0

x^{2} - x (6 - 1) - 6 = 0

solvefor x,2x^2+p^2=(q-x)^2

so l v e f or x, 2 x^{2} + p^{2} = (q - x)^{2}

a \cdot x^{2} - 8 x + 4 = 0

solvefor x,x^2y^2+x^2+y^2=3736

so l v e f or x, x^{2} y^{2} + x^{2} + y^{2} = 3736