4x^2-24x+5=0

解答

4 x^{2} - 24 x + 5 = 0

x = \frac{6 + 31}{2}, x = \frac{6 - 31}{2}

十进制

x = 5.78388 \dots, x = 0.21611 \dots

求解步骤

4 x^{2} - 24 x + 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 5 = 431

x_{1, 2} = \frac{- ( - 24 ) \pm 4 31}{2 \cdot 4}

将解分隔开

x_{1} = \frac{- ( - 24 ) + 4 31}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 4 31}{2 \cdot 4}

x = \frac{- ( - 24 ) + 4 31}{2 \cdot 4} : \frac{6 + 31}{2}

x = \frac{- ( - 24 ) - 4 31}{2 \cdot 4} : \frac{6 - 31}{2}

二次方程组的解是:

x = \frac{6 + 31}{2}, x = \frac{6 - 31}{2}

so l v e f or x, z = 2 x y - x^{2} - 2 y^{2} + 4 y

so l v e f or h, 2 h^{2} + o^{2} = 2 h^{2} o

0.25 x^{2} + 0.75 x - 0.1875 = 0

a^{0.2} x (7 x + 5) - 7 x (2 x - 3) = 93

so l v e f or x, z = \frac{( x ^{2} + 1 )}{( 1 - 2 y )}