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受欢迎的代数 >

solvefor x,a*y=x^2+2(x+1)

解答

求解

x, a \cdot y = x^{2} + 2 (x + 1)

解答

x = - 1 + a y - 1, x = - a y - 1 - 1

求解步骤

a y = x^{2} + 2 (x + 1)

展开

x^{2} + 2 (x + 1) : x^{2} + 2 x + 2

a y = x^{2} + 2 x + 2

交换两边

x^{2} + 2 x + 2 = a y

将

a \cdot y

para o lado esquerdo

x^{2} + 2 x + 2 - a y = 0

使用求根公式求解

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( 2 - a y )}{2 \cdot 1}

化简

2^{2} - 4 \cdot 1 \cdot (2 - a y) : 2 a y - 1

x_{1, 2} = \frac{- 2 \pm 2 a y - 1}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- 2 + 2 a y - 1}{2 \cdot 1}, x_{2} = \frac{- 2 - 2 a y - 1}{2 \cdot 1}

x = \frac{- 2 + 2 a y - 1}{2 \cdot 1} : - 1 + a y - 1

x = \frac{- 2 - 2 a y - 1}{2 \cdot 1} : - a y - 1 - 1

二次方程组的解是:

x = - 1 + a y - 1, x = - a y - 1 - 1

作图

流行的例子

a = x^{2} + 16 x - 5

(y+1/4)^2= 9/16

(y + \frac{1}{4})^{2} = \frac{9}{16}

2.5 x^{2} + 4 x + 1 = 0

solvefor x,y^2(a^2+x^2)=a^2x^2

so l v e f or x, y^{2} (a^{2} + x^{2}) = a^{2} x^{2}

(y+k)^2-2y^2-2(k+1)y-10=0

(y + k)^{2} - 2 y^{2} - 2 (k + 1) y - 10 = 0