solvefor x,x^2p+y^2q=z^2

解

解く

x, x^{2} p + y^{2} q = z^{2}

x = \frac{z ^{2} - y ^{2} q}{p}, x = - \frac{z ^{2} - y ^{2} q}{p}; p \neq = 0

解答ステップ

x^{2} p + y^{2} q = z^{2}

y^{2} q

を右側に移動します

x^{2} p = z^{2} - y^{2} q

以下で両辺を割る

p; p \neq = 0

x^{2} = \frac{z ^{2} - y ^{2} q}{p}; p \neq = 0

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = \frac{z ^{2} - y ^{2} q}{p}, x = - \frac{z ^{2} - y ^{2} q}{p}; p \neq = 0