2^x=5^{x+2}

Lösung

2^{x} = 5^{x + 2}

x = \frac{2 ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

Dezimale

x = - 3.51294 \dots

Schritte zur Lösung

2^{x} = 5^{x + 2}

Wende Exponentenregel an

x ln (2) = (x + 2) ln (5)

Löse

x ln (2) = (x + 2) ln (5) : x = \frac{2 ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

x = \frac{2 ln ( 5 )}{ln ( 2 ) - ln ( 5 )}

x^{x} = 2

3^{x} - 54 x + 135 = 0

2^{x^{2} - 4} = 3^{x^{2} - 4}

9^{x} + 3 3^{x} = 12 1^{x}

\frac{2 ^{x - 1} + 1}{( 2 ^{x - 3} )} = 5