11^{x-4}=8^{-4x}

Lösung

1 1^{x - 4} = 8^{- 4 x}

x = \frac{4 ln ( 11 )}{ln ( 11 ) + 12 ln ( 2 )}

Dezimale

x = 0.89509 \dots

Schritte zur Lösung

1 1^{x - 4} = 8^{- 4 x}

Wende Exponentenregel an

(x - 4) ln (11) = - 4 x ln (8)

Löse

(x - 4) ln (11) = - 4 x ln (8) : x = \frac{4 ln ( 11 )}{ln ( 11 ) + 12 ln ( 2 )}

x = \frac{4 ln ( 11 )}{ln ( 11 ) + 12 ln ( 2 )}

so l v e f or x, e^{x + y} = 2^{x + y}

5^{x} = 1

x^{x} = 2^{2048}

e^{x} = 1

2^{n} = 5