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受欢迎的代数 >

solvefor x,[t]=[p^xd^ye^2]

解答

求解

x, [t] = [p^{x} \cdot d^{y} \cdot e^{2}]

解答

x = \frac{ln ( \frac{t}{e ^{2} d ^{y}} )}{ln ( p )}

求解步骤

[t] = [p^{x} d^{y} e^{2}]

交换两边

[p^{x} d^{y} e^{2}] = [t]

[p^{x} d^{y} e^{2}] = t

两边除以

e^{2} d^{y}

p^{x} = \frac{t}{e ^{2} d ^{y}}

使用指数运算法则

x ln (p) = ln (\frac{t}{e ^{2} d ^{y}})

解

x ln (p) = ln (\frac{t}{e ^{2} d ^{y}}) : x = \frac{ln ( \frac{t}{e ^{2} d ^{y}} )}{ln ( p )}

x = \frac{ln ( \frac{t}{e ^{2} d ^{y}} )}{ln ( p )}

作图

流行的例子

5^{6 x + 8} = 12 5^{4}

(- 4)^{x} = 1024

2^{a-2}+2^{3-a}=3

2^{a - 2} + 2^{3 - a} = 3

2^{x} + 2^{3} x = 16

2^{x} = 0.5