2^{3x+3}=2^{3x+1}+48

Lösung

2^{3 x + 3} = 2^{3 x + 1} + 48

x = 1

Schritte zur Lösung

2^{3 x + 3} = 2^{3 x + 1} + 48

Wende Exponentenregel an

3 x = 3

Löse

3 x = 3 : x = 1

x = 1

4^{2 x} + 2 0^{x} = 5^{2 x}

(5^{k})^{2} = \frac{12 5 ^{3}}{( 5 ^{2} )}

2^{2 x + 6 x} - 16 = 0

100 = 5^{b}

0.9711 n - 0.9711 = (0.9614)^{n}