2^{1-x}= 1/81

Lösung

2^{1 - x} = \frac{1}{81}

x = \frac{ln ( 162 )}{ln ( 2 )}

Dezimale

x = 7.33985 \dots

Schritte zur Lösung

2^{1 - x} = \frac{1}{81}

Wende Exponentenregel an

(1 - x) ln (2) = ln (\frac{1}{81})

Löse

(1 - x) ln (2) = ln (\frac{1}{81}) : x = \frac{ln ( 162 )}{ln ( 2 )}

x = \frac{ln ( 162 )}{ln ( 2 )}

3^{n} = 9 n

1 0^{1} - x = 6^{x}

1 1^{- 3 x} = 1 7^{x - 6}

7^{x + 2} + 7^{x + 1} = 8

12000 = 200 e^{0.01 t}