solvefor a,2^{a-b}=2016

Lösung

löse nach

a, 2^{a - b} = 2016

a = \frac{ln ( 2016 )}{ln ( 2 )} + b

Schritte zur Lösung

2^{a - b} = 2016

Wende Exponentenregel an

(a - b) ln (2) = ln (2016)

Löse

(a - b) ln (2) = ln (2016) : a = \frac{ln ( 2016 )}{ln ( 2 )} + b

a = \frac{ln ( 2016 )}{ln ( 2 )} + b

3^{x} + 3^{x + 2} = 7290

\frac{5}{2 \cdot 2 ^{x} - 2 ^{x} - 2 ^{- 1}} = 16

1 1^{9 x} = 4^{- x + 7}

7^{x} - 2^{x} = 0

2^{x} = n