2^x= 4/9

Lösung

2^{x} = \frac{4}{9}

x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

Dezimale

x = - 1.16992 \dots

Schritte zur Lösung

2^{x} = \frac{4}{9}

Wende Exponentenregel an

x ln (2) = ln (\frac{4}{9})

Löse

x ln (2) = ln (\frac{4}{9}) : x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

2^{x} \cdot 4^{x} = 8^{\frac{1}{3}}

3^{x} + 1 = 4

3 \cdot 2^{x} = 15

(\frac{3}{4})^{1 - 3 x} = \frac{210}{27}

so l v e f or x, 9^{x - 1} = 24 3^{y + 2}