27^{x-1}=(1/9)^x

Lösung

2 7^{x - 1} = (\frac{1}{9})^{x}

x = \frac{3}{5}

Dezimale

x = 0.6

Schritte zur Lösung

2 7^{x - 1} = (\frac{1}{9})^{x}

Wende Exponentenregel an

3 (x - 1) = - 2 x

Löse

3 (x - 1) = - 2 x : x = \frac{3}{5}

x = \frac{3}{5}

so l v e f or x, 2 u + 3 v = e^{x} (cos (y) - sin (y))

e^{y} = 0

2^{x + 3} = 4^{x - 1}

2^{x + 1} + 2^{x} - 2^{x} - 2 = 88

2 = (1.05)^{n}