(x^2+3x-20)/(x^2+3x)=8

解

\frac{x ^{2} + 3 x - 20}{x ^{2} + 3 x} = 8

x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}

解答ステップ

\frac{x ^{2} + 3 x - 20}{x ^{2} + 3 x} = 8

以下で両辺を乗じる:

x^{2} + 3 x

x^{2} + 3 x - 20 = 8 (x^{2} + 3 x)

解く

x^{2} + 3 x - 20 = 8 (x^{2} + 3 x) : x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}

x = - \frac{3}{2} - i \frac{119}{14}, x = - \frac{3}{2} + i \frac{119}{14}