((2x-1)}{3+x}=\frac{(2x+6))/5

解答

\frac{( 2 x - 1 )}{3 + x} = \frac{( 2 x + 6 )}{5}

x = - \frac{1}{2} + i \frac{3 5}{2}, x = - \frac{1}{2} - i \frac{3 5}{2}

求解步骤

\frac{( 2 x - 1 )}{3 + x} = \frac{( 2 x + 6 )}{5}

使用分式交叉相乘

(2 x - 1) \cdot 5 = (3 + x) (2 x + 6)

解

(2 x - 1) \cdot 5 = (3 + x) (2 x + 6) : x = - \frac{1}{2} + i \frac{3 5}{2}, x = - \frac{1}{2} - i \frac{3 5}{2}

x = - \frac{1}{2} + i \frac{3 5}{2}, x = - \frac{1}{2} - i \frac{3 5}{2}

\frac{ln ( e ) ( \frac{1}{2} ) + 1}{y} = 1

x = \frac{1}{2 x ^{2}}

\frac{6}{x} - 1 + \frac{3}{x} + 1 = \frac{28}{x ^{2}} - 1

so l v e f or a, b = \frac{r}{( 2 ( a + r ) )}

\frac{x + 2}{x + 3} = 0