3x^2-4|x^2-1|+x-1=0

Lösung

3 x^{2} - 4 x^{2} - 1 + x - 1 = 0

x = - \frac{- 1 + 13}{2} or x = \frac{- 1 - 141}{14} or x = \frac{- 1 + 141}{14} or x = \frac{1 + 13}{2}

Dezimale

x = - 1.30277 \dots, x = - 0.91959 \dots, x = 0.77673 \dots, x = 2.30277 \dots

Schritte zur Lösung

3 x^{2} - 4 x^{2} - 1 + x - 1 = 0

Finde positive und negative Intervalle

x \leq - 1, - 1 < x < 1, x \geq 1

Löse die Ungleichung für jedes Intervall

x = - \frac{- 1 + 13}{2} or (x = \frac{- 1 - 141}{14} or x = \frac{- 1 + 141}{14}) or x = \frac{1 + 13}{2}

x = - \frac{- 1 + 13}{2} or x = \frac{- 1 - 141}{14} or x = \frac{- 1 + 141}{14} or x = \frac{1 + 13}{2}

∣ x - 2 ∣ + ∣ x - 5 ∣ = 3

∣ x - 1 ∣ - ∣ x ∣ + ∣ x + 1 ∣ = 2

x^{2} - 2 ∣ x ∣ - 2 = 1

7 ∣ x - 2 ∣ - ∣ x - 7 ∣ = 5

x^{2} + ∣ x - 1 ∣ = 1