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Popular >

x/(log_{332)(x)+1}=15

Solución

\frac{x}{lo g _{332} ( x ) + 1} = 15

Solución

x = - \frac{15 W _{- 1} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}, x = - \frac{15 W _{0} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

+1

Notación decimal

x = 23.11471 \dots, x = 0.00301 \dots

Pasos de solución

\frac{x}{lo g _{332} ( x ) + 1} = 15

Multiplicar ambos lados por

lo g_{332} (x) + 1

x = 15 (lo g_{332} (x) + 1)

Intercambiar lados

15 (lo g_{332} (x) + 1) = x

Dividir ambos lados entre

15

lo g_{332} (x) + 1 = \frac{x}{15}

Mover

1

al lado derecho

lo g_{332} (x) = \frac{x}{15} - 1

Si

f (x) = g (x),

entonces

a^{f (x)} = a^{g (x)}

33 2^{l o g_{332} (x)} = 33 2^{\frac{x}{15} - 1}

Simplificar

33 2^{l o g_{332} (x)} : x

x = 33 2^{\frac{x}{15} - 1}

Resolver

x = 33 2^{\frac{x}{15} - 1} : x = - \frac{15 W _{- 1} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}, x = - \frac{15 W _{0} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

x = - \frac{15 W _{- 1} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}, x = - \frac{15 W _{0} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

Verificar las soluciones:

x = - \frac{15 W _{- 1} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

Verdadero

, x = - \frac{15 W _{0} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

Verdadero

Las soluciones son

x = - \frac{15 W _{- 1} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}, x = - \frac{15 W _{0} ( - \frac{l n ( 332 )}{4980} )}{ln ( 332 )}

Ejemplos populares

log_{10}(81x)= 1/4

lo g_{10} (81 x) = \frac{1}{4}

log_{10}(x)+log_{10}(x-21)=2

lo g_{10} (x) + lo g_{10} (x - 21) = 2

log_{3}(2x+1)+log_{3}(x+8)=3

lo g_{3} (2 x + 1) + lo g_{3} (x + 8) = 3

ln (x - 1) = 1

4*log_{10}(x)=3*(-0.6655)

4 \cdot lo g_{10} (x) = 3 \cdot (- 0.6655)