log_{3}((2+x)^2)=6

Lösung

lo g_{3} ((2 + x)^{2}) = 6

x = 25, x = - 29

Schritte zur Lösung

lo g_{3} ((2 + x)^{2}) = 6

Wende die log Regel an

(2 + x)^{2} = 729

Löse

(2 + x)^{2} = 729 : x = 25, x = - 29

x = 25, x = - 29

lo g_{3} (x - 5) + lo g_{3} (x + 2) = lo g_{3} (8)

lo g_{10} (x) + lo g_{10} (x + 3) = 2 lo g_{10} (x + 1)

so l v e f or x, (lo g_{2} (x))^{2} = \frac{1}{f}

2 lo g_{10} (x) = 3 + lo g_{10} (x)

lo g_{10} (10 m) = 4