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Beliebt Algebra >

x=-2+t^2,y=1-2t^2

Lösung

x = - 2 + t^{2}, y = 1 - 2 t^{2}

Lösung

4 t^{4} - 4 t^{2} - 1

Schritte zur Lösung

Finde

x \circ y

gegeben

x = - 2 + t^{2}, y = 1 - 2 t^{2}

x \circ y = (x) ((y) (t))

y = 1 - 2 t^{2}

= (x) (1 - 2 t^{2})

(x) (1 - 2 t^{2}) : 4 t^{4} - 4 t^{2} - 1

= 4 t^{4} - 4 t^{2} - 1

Beliebte Beispiele

x - 2 y = 1, 2 x - 4 y = 2

[n]yf(y)(y)^2=50[n],f(y)(y)^1=20

[n] y f (y) (y)^{2} = 50 [n], f (y) (y)^{1} = 20

8/x+5/y =-3, 6/x+(25)/y =2

\frac{8}{x} + \frac{5}{y} = - 3, \frac{6}{x} + \frac{25}{y} = 2

y=(2/3)x+4,-2x+3y=6

y = (\frac{2}{3}) x + 4, - 2 x + 3 y = 6

2x+y-2z=1,x-2y+3z=6,3x-3y-z=5

2 x + y - 2 z = 1, x - 2 y + 3 z = 6, 3 x - 3 y - z = 5