What is x+y=11,y+2= 1/8*(10y+x)*1 ?

The solution to x+y=11,y+2= 1/8*(10y+x)*1 is x=6,y=5

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x+y=11,y+2= 1/8(10y+x)1

x + y = 11, y + 2 = \frac{1}{8} \cdot (10 y + x) \cdot 1

x = 6, y = 5

Solution steps

[x + y = 11 y + 2 = \frac{1}{8} (10 y + x) \cdot 1]

Isolate

x

for

x + y = 11 : x = 11 - y

Substitute

x = 11 - y

[y + 2 = \frac{1}{8} (10 y + 11 - y) \cdot 1]

Simplify

[y + 2 = \frac{9 y + 11}{8}]

Isolate

y

for

y + 2 = \frac{9 y + 11}{8} : y = 5

For

x = 11 - y

Substitute

y = 5

x = 11 - 5

Simplify

x = 6

The solutions to the system of equations are:

x = 6, y = 5

- 8 x + 7 y = - 3, 3 x - 7 y = - 12

2 - 5 x = 17, 2 - 5 x = 17

25 x + 10 y = 50, - 6 x + 10 y = 24

8 x + 2 y - 4 z = 16, 4 x + 10 y + 10 z = - 6, 3 x + 8 y + 6 z = 18

2^{a} = 3, 3^{b} = 4, 4^{c} = 5

What is x+y=11,y+2= 1/8*(10y+x)*1 ?
The solution to x+y=11,y+2= 1/8*(10y+x)*1 is x=6,y=5