ja

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

人気のある代数 >

35x^2-12x+1=0,20y^2-14y+2=0

解

35 x^{2} - 12 x + 1 = 0, 20 y^{2} - 14 y + 2 = 0

解

x = \frac{1}{7}, x = \frac{1}{7}, x = \frac{1}{5}, x = \frac{1}{5}, y = \frac{1}{2} y = \frac{1}{5} y = \frac{1}{2} y = \frac{1}{5}

解答ステップ

[35 x^{2} - 12 x + 1 = 0 20 y^{2} - 14 y + 2 = 0]

解く

35 x^{2} - 12 x + 1 = 0 : x = \frac{1}{7}, x = \frac{1}{5}

20 y^{2} - 14 y + 2 = 0

では,

x

を

\frac{1}{7}

に置き換える:

y = \frac{1}{2}, y = \frac{1}{5}

20 y^{2} - 14 y + 2 = 0

では,

x

を

\frac{1}{5}

に置き換える:

y = \frac{1}{2}, y = \frac{1}{5}

解く

20 y^{2} - 14 y + 2 = 0 : y = \frac{1}{5}, y = \frac{1}{2}

35 x^{2} - 12 x + 1 = 0

では,

y

を

\frac{1}{5}

に置き換える:

x = \frac{1}{5}, x = \frac{1}{7}

35 x^{2} - 12 x + 1 = 0

では,

y

を

\frac{1}{2}

に置き換える:

x = \frac{1}{5}, x = \frac{1}{7}

元のequationに当てはめて解を検算する

ゆえに,

35 x^{2} - 12 x + 1 = 0, 20 y^{2} - 14 y + 2 = 0

の最終的な解は

x = \frac{1}{7}, x = \frac{1}{7}, x = \frac{1}{5}, x = \frac{1}{5}, y = \frac{1}{2} y = \frac{1}{5} y = \frac{1}{2} y = \frac{1}{5}

グラフ

人気の例

y^{2} x - 7 y = 10, x = 6

5 x/6-y/4 =-2,3r+2n=3

5 \frac{x}{6} - \frac{y}{4} = - 2, 3 r + 2 n = 3

a=(81)/(3^3)-xy,b=2^3-xy

a = \frac{81}{3 ^{3}} - x y, b = 2^{3} - x y

18x-24y=6,18x-24y=-45

18 x - 24 y = 6, 18 x - 24 y = - 45

3x+y=4,2y^5x+3y=78

3 x + y = 4, 2 y^{5} x + 3 y = 78