(x-1)(x-5)(x-15)<= 0,(x-3)(x-10)>0

解答

(x - 1) (x - 5) (x - 15) \leq 0, (x - 3) (x - 10) > 0

x \leq 1 or 5 \leq x \leq 15

间隔符号

(- \infty, 1] \cup [5, 15]

求解步骤

(x - 1) (x - 5) (x - 15) \leq 0

确定区间

x \leq 1 or 5 \leq x \leq 15

[x + 6] > 4

\frac{( x + 5 ) ( x - 9 )}{( x - 12 )} > 0

(x^{2} - 4) (x^{3} - 5 x^{2} + 6 x) \geq 0

x^{3} - 6 x^{2} + 11 x - 6 < 0

\frac{( x + 3 )}{3} - \frac{4}{( x + 2 )} > \frac{x}{3}