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Beliebt Algebra >

x^3+5x^2+4x>= 0

Lösung

x^{3} + 5 x^{2} + 4 x \geq 0

Lösung

- 4 \leq x \leq - 1 or x \geq 0

+1

Intervall-Notation

[- 4, - 1] \cup [0, \infty)

Schritte zur Lösung

x^{3} + 5 x^{2} + 4 x \geq 0

Faktorisiere

x^{3} + 5 x^{2} + 4 x : x (x + 1) (x + 4)

x (x + 1) (x + 4) \geq 0

Identifiziere die Intervalle

- 4 \leq x \leq - 1 or x \geq 0

Graph

Beliebte Beispiele

(2 - x) (x + 3) > 0

solvefor x,2(2x-1)>4x-6u

so l v e f or x, 2 (2 x - 1) > 4 x - 6 u

((x+1)(x-1)(x+2))/((x^2+3x+2)(x+5))<0

\frac{( x + 1 ) ( x - 1 ) ( x + 2 )}{( x ^{2} + 3 x + 2 ) ( x + 5 )} < 0

x (x^{2} - 1) \leq 0

(((x+2)(x^2-2x+1)))/((-4+3x-2x^2))>= 0

\frac{( ( x + 2 ) ( x ^{2} - 2 x + 1 ) )}{( - 4 + 3 x - 2 x ^{2} )} \geq 0