((x-2)^2(x-1))/((x-3))>= 0

解答

\frac{( x - 2 ) ^{2} ( x - 1 )}{( x - 3 )} \geq 0

x \leq 1 or x = 2 or x > 3

间隔符号

(- \infty, 1] \cup x = 2 \cup (3, \infty)

求解步骤

\frac{( x - 2 ) ^{2} ( x - 1 )}{x - 3} \geq 0

确定区间

x \leq 1 or x = 2 or x > 3

\frac{1}{( n - 2 )} + \frac{1}{( n - 1 )} > \frac{1}{n}

(x - 2) (x - 3) (x + 2) (x + 3) > 0

x (9 x - 4) < (3 x + 2)^{2}

(x - 1)^{2021} (x + 1)^{2022} < 0

3 x^{12} > 0