((x^2-1))/((x^2))>0

解答

\frac{( x ^{2} - 1 )}{( x ^{2} )} > 0

x < - 1 or x > 1

间隔符号

(- \infty, - 1) \cup (1, \infty)

求解步骤

\frac{x ^{2} - 1}{x ^{2}} > 0

分解

\frac{x ^{2} - 1}{x ^{2}} : \frac{( x + 1 ) ( x - 1 )}{x ^{2}}

\frac{( x + 1 ) ( x - 1 )}{x ^{2}} > 0

确定区间

x < - 1 or x > 1

\frac{1}{( x + 1 )} < \frac{2}{( 3 x - 1 )}

(2 x^{2} - 13 x - 27) (x^{2} - 2 x + 6) \leq 0

x^{2} - 3 x + 4 > - 2

\frac{- 1}{2 x} > 6

\frac{( x ^{3} + x ^{2} + x )}{( 9 x ^{2} - 25 )} \geq 0