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Beliebt Algebra >

(x^2-9)^2*(x+1)(x^2-2x-3)(x-1)>= 0

Lösung

(x^{2} - 9)^{2} \cdot (x + 1) (x^{2} - 2 x - 3) (x - 1) \geq 0

Lösung

x \leq 1 or x \geq 3

+1

Intervall-Notation

(- \infty, 1] \cup [3, \infty)

Schritte zur Lösung

(x^{2} - 9)^{2} (x + 1) (x^{2} - 2 x - 3) (x - 1) \geq 0

Faktorisiere

(x^{2} - 9)^{2} (x + 1) (x^{2} - 2 x - 3) (x - 1) : (x - 3)^{3} (x + 3)^{2} (x + 1)^{2} (x - 1)

(x - 3)^{3} (x + 3)^{2} (x + 1)^{2} (x - 1) \geq 0

Identifiziere die Intervalle

x \leq 1 or x \geq 3

Graph

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