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Beliebt Algebra >

(x+1)^2(x-1)^3(x-5)^7>= 0

Lösung

(x + 1)^{2} \cdot (x - 1)^{3} \cdot (x - 5)^{7} \geq 0

Lösung

x \leq 1 or x \geq 5

+1

Intervall-Notation

(- \infty, 1] \cup [5, \infty)

Schritte zur Lösung

(x + 1)^{2} (x - 1)^{3} (x - 5)^{7} \geq 0

Identifiziere die Intervalle

x \leq 1 or x \geq 5

Graph

Beliebte Beispiele

(x^2+1)(x^2-1)<= 0

(x^{2} + 1) (x^{2} - 1) \leq 0

\frac{x}{2 x} < 9

(x+1)/((x-1))<= 3

\frac{x + 1}{( x - 1 )} \leq 3

5x^3-17x^2+17x-5<= 0

5 x^{3} - 17 x^{2} + 17 x - 5 \leq 0

(x+2)^2-(x-2)^2>8x-2

(x + 2)^{2} - (x - 2)^{2} > 8 x - 2