(x+1)(x-2)(x-3)<= 0

Lösung

(x + 1) (x - 2) (x - 3) \leq 0

x \leq - 1 or 2 \leq x \leq 3

Intervall-Notation

(- \infty, - 1] \cup [2, 3]

Schritte zur Lösung

(x + 1) (x - 2) (x - 3) \leq 0

Identifiziere die Intervalle

x \leq - 1 or 2 \leq x \leq 3

4 x^{2} + 20 x = - 21

4 x^{2} + x = 0

- 8 < - 2 z + 4 < 10

- \frac{3}{4} (x + 2) = 6

x^{2} - x - 9 = 0