((x-3))/((x^2+9x-22))<0

解答

\frac{( x - 3 )}{( x ^{2} + 9 x - 22 )} < 0

x < - 11 or 2 < x < 3

间隔符号

(- \infty, - 11) \cup (2, 3)

求解步骤

\frac{x - 3}{x ^{2} + 9 x - 22} < 0

分解

\frac{x - 3}{x ^{2} + 9 x - 22} : \frac{x - 3}{( x - 2 ) ( x + 11 )}

\frac{x - 3}{( x - 2 ) ( x + 11 )} < 0

确定区间

x < - 11 or 2 < x < 3

4 x^{2} - 4 x + 3 < 0

\frac{( 2 x - 3 )}{6} - \frac{( x - 1 )}{2} > 7

\frac{x}{2} + 1 \leq \frac{x}{( 3 )} + \frac{1}{2}

7 + 4 x < 13

6 u > 54