| 2/((x-4))|>1

Lösung

\frac{2}{( x - 4 )} > 1

2 < x < 4 or 4 < x < 6

Intervall-Notation

(2, 4) \cup (4, 6)

Schritte zur Lösung

\frac{2}{x - 4} > 1

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

\frac{2}{x - 4} < - 1 or \frac{2}{x - 4} > 1

\frac{2}{x - 4} < - 1 or \frac{2}{x - 4} > 1

2 < x < 4 or 4 < x < 6

x^{2} - 6 x + 9 \geq 4

\frac{3}{x + 1} > 2

∣ 2 x ∣ 3 - x ∣ - 2 ∣ \leq 4

∣ 2 x - 11 ∣ > - 3

\frac{x + 2}{x} < 3