|3d-3|>12

Lösung

∣ 3 d - 3 ∣ > 12

d < - 3 or d > 5

Intervall-Notation

(- \infty, - 3) \cup (5, \infty)

Schritte zur Lösung

∣ 3 d - 3 ∣ > 12

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

3 d - 3 < - 12 or 3 d - 3 > 12

3 d - 3 < - 12 or 3 d - 3 > 12

d < - 3 or d > 5

∣ x - 4 ∣ + 2 ∣ x - 3 ∣ \geq 4

∣ 2 x + 7 ∣ < ∣ 5 ∣

(1 + x^{2}) \geq 1 - x^{2}

∣ x + 1 ∣ + ∣ x - 4 ∣ > 7

∣ m - 1 ∣ > ∣ m + 3 ∣