簡約 (5x-7)(3x-2)-(4x-5)(6x-1)

解

簡約

(5 x - 7) (3 x - 2) - (4 x - 5) (6 x - 1)

- 9 x^{2} + 3 x + 9

解答ステップ

(5 x - 7) (3 x - 2) - (4 x - 5) (6 x - 1)

拡張

(5 x - 7) (3 x - 2) : 15 x^{2} - 31 x + 14

= 15 x^{2} - 31 x + 14 - (4 x - 5) (6 x - 1)

拡張

- (4 x - 5) (6 x - 1) : - 24 x^{2} + 34 x - 5

= 15 x^{2} - 31 x + 14 - 24 x^{2} + 34 x - 5

条件のようなグループ

= 15 x^{2} - 24 x^{2} - 31 x + 34 x + 14 - 5

類似した元を足す:

15 x^{2} - 24 x^{2} = - 9 x^{2}

= - 9 x^{2} - 31 x + 34 x + 14 - 5

類似した元を足す:

- 31 x + 34 x = 3 x

= - 9 x^{2} + 3 x + 14 - 5

数を引く:

14 - 5 = 9

= - 9 x^{2} + 3 x + 9