faktorisieren 2cos^2(x)-7cos(x)+3

Lösung

faktorisieren

2 cos^{2} (x) - 7 cos (x) + 3

(2 cos (x) - 1) (cos (x) - 3)

Schritte zur Lösung

2 cos^{2} (x) - 7 cos (x) + 3

Zerlege die Ausdrücke in Gruppen

= (2 cos^{2} (x) - cos (x)) + (- 6 cos (x) + 3)

Klammere

cos (x)

aus

2 cos^{2} (x) - cos (x)

aus

: cos (x) (2 cos (x) - 1)

Klammere

- 3

aus

- 6 cos (x) + 3

aus

: - 3 (2 cos (x) - 1)

= cos (x) (2 cos (x) - 1) - 3 (2 cos (x) - 1)

Klammere gleiche Terme aus

2 cos (x) - 1

= (2 cos (x) - 1) (cos (x) - 3)

f a c t or 6 (3 r - 1)^{2} + (3 r - 1) - 35

f a c t or (- \infty) + \infty

f a c t or - cos (10 a + 2 θ) sin (10 a + 2 θ)

f a c t or (u \cdot v) \cdot (x \cdot b)

f a c t or \frac{5}{1}