解答
因式分解 sin25(x)+cos25(x)
解答
(sin(x)+cos(x))(sin24(x)−sin23(x)cos(x)+sin22(x)cos2(x)−sin21(x)cos3(x)+sin20(x)cos4(x)−sin19(x)cos5(x)+sin18(x)cos6(x)−sin17(x)cos7(x)+sin16(x)cos8(x)−sin15(x)cos9(x)+sin14(x)cos10(x)−sin13(x)cos11(x)+sin12(x)cos12(x)−cos13(x)sin11(x)+cos14(x)sin10(x)−cos15(x)sin9(x)+cos16(x)sin8(x)−cos17(x)sin7(x)+cos18(x)sin6(x)−cos19(x)sin5(x)+cos20(x)sin4(x)−cos21(x)sin3(x)+cos22(x)sin2(x)−cos23(x)sin(x)+cos24(x))
求解步骤
sin25(x)+cos25(x)
使用因式分解法则 xn+yn=(x+y)(xn−1−xn−2y+…−xyn−2+yn−1)n is oddsin25(x)+cos25(x)=(sin(x)+cos(x))(sin24(x)−sin23(x)cos(x)+sin22(x)cos2(x)−sin21(x)cos3(x)+sin20(x)cos4(x)−sin19(x)cos5(x)+sin18(x)cos6(x)−sin17(x)cos7(x)+sin16(x)cos8(x)−sin15(x)cos9(x)+sin14(x)cos10(x)−sin13(x)cos11(x)+sin12(x)cos12(x)−sin11(x)cos13(x)+sin10(x)cos14(x)−sin9(x)cos15(x)+sin8(x)cos16(x)−sin7(x)cos17(x)+sin6(x)cos18(x)−sin5(x)cos19(x)+sin4(x)cos20(x)−sin3(x)cos21(x)+sin2(x)cos22(x)−sin(x)cos23(x)+cos24(x))=(sin(x)+cos(x))(sin24(x)−sin23(x)cos(x)+sin22(x)cos2(x)−sin21(x)cos3(x)+sin20(x)cos4(x)−sin19(x)cos5(x)+sin18(x)cos6(x)−sin17(x)cos7(x)+sin16(x)cos8(x)−sin15(x)cos9(x)+sin14(x)cos10(x)−sin13(x)cos11(x)+sin12(x)cos12(x)−sin11(x)cos13(x)+sin10(x)cos14(x)−sin9(x)cos15(x)+sin8(x)cos16(x)−sin7(x)cos17(x)+sin6(x)cos18(x)−sin5(x)cos19(x)+sin4(x)cos20(x)−sin3(x)cos21(x)+sin2(x)cos22(x)−sin(x)cos23(x)+cos24(x))