faktorisieren 5y(8-3z)^2-(1-5z)^2

Lösung

faktorisieren

5 y (8 - 3 z)^{2} - (1 - 5 z)^{2}

320 y - 240 yz + 45 y z^{2} - 1 + 10 z - 25 z^{2}

Schritte zur Lösung

5 y (8 - 3 z)^{2} - (1 - 5 z)^{2}

(8 - 3 z)^{2} : 64 - 48 z + 9 z^{2}

= 5 y (64 - 48 z + 9 z^{2}) - (1 - 5 z)^{2}

(1 - 5 z)^{2} : 1 - 10 z + 25 z^{2}

= 5 y (64 - 48 z + 9 z^{2}) - (1 - 10 z + 25 z^{2})

Multipliziere aus

5 y (64 - 48 z + 9 z^{2}) : 320 y - 240 yz + 45 y z^{2}

= 320 y - 240 yz + 45 y z^{2} - (1 - 10 z + 25 z^{2})

- (1 - 10 z + 25 z^{2}) : - 1 + 10 z - 25 z^{2}

= 320 y - 240 yz + 45 y z^{2} - 1 + 10 z - 25 z^{2}

f a c t or (x + 2)^{2} - 14

f a c t or 8 m^{2} n^{4} + 4 m^{2} n^{4}

s im pl i f y B (1.1)

f a c t or \frac{( x ^{3} - 8 )}{x - 2}

f (x) = 7 (sin (x))^{6} \cdot cos (x)